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Answers and rating deltas for
Ruby -- use a string as a variable name to define a new variable
| Author | Votes | Δ |
|---|---|---|
| Danil Speransky | 5 | +0.49 |
| J.Doe | 0 | -1.95 |
| Michael Yurkovetc | 0 | -1.95 |
Last visited: Dec 1, 2017, 2:11:24 AM