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How to solve the recurrence of T(n) = 2 * T(n/3) + 3/2 * T(n/4) + 5 * T(n/2) + Theta(n^2), p = 2,574
| Author | Votes | Δ |
|---|---|---|
| OmG | 1 | 0.00 |
Last visited: Sep 5, 2020, 12:36:14 PM