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In Perl, is there any scenario in which ${foo[bar]} could be syntactically valid code?
| Author | Votes | Δ |
|---|---|---|
| tchrist | 8 | +0.84 |
| Julian Fondren | 4 | +0.38 |
| Hynek -Pichi- Vychodil | 0 | -0.89 |
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