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Rating Stats for

G. Grothendieck

Rating
1622.82 (1,021st)

Reputation
165,339 (319th)

Page: 1 ... 61 62 63 64 65 ... 105

Title	Δ
replace NA or else <NA> with something or something else in c...	+0.37
how can i retrieve information from pubmed	0.00
R, rename thousands of downloaded files	0.00
parsing german numbers within string-vector	+1.64
Merging two rows with some having missing values in R	+0.21
R programming - assigning an index to number the instances of date...	-0.39
Transforming data from xml into R dataframe	0.00
How to create a function which removes a certain first character of...	0.00
Differentiating and lagging values of one df	+0.37
R package with code that only runs once (per installation)	+1.76
Set new variable NA if any other is NA	+0.91
Add missing dates with previous values in R - converting quarterly...	0.00
how to apply a function over dataframe colum in month wise and show...	-2.33
Fitting Transmuted Pareto Distribution And Calculation of Hessian M...	0.00
How to ignore linearly correlated variables introduced by factor re...	0.00
how to calculate total time served by employee in R	-0.15
split column based on 2 columns	+0.37
How to return elements of R list as independent objects in function...	0.00
R - using aggregate on several variables and combine unique values	+0.37
How to cast nested list to matrix like or tabular like object?	0.00
more columns than column name on txt file	0.00
Total rows does not contain a factor and the value is not zero	0.00
How to mix daily and quarterly data in R?	0.00
Aggregate function in R zoo returns error	0.00
Add single quote to start and end of the vector of a string which w...	-0.15
Get row indices of data frame A according to multiple matching crit...	0.00
Use grouped summary to operate in another data.frame column by factor	0.00
Query returning 0 rows with sqldf package	0.00
Split a single column into multiple columns based on a set of values	+1.84
R - Removing only one part of the empty rows of a zoo objects	0.00
Return second last date	-2.76
sqldf R - days between orders - group by client	0.00
How to split in R a date range into quarterly basis period?	-0.42
R: Transforming incomplete timeseries into matrix	0.00
How do I get RSS from a linear model output	0.00
Pipe output of more than one variable using tidyr::map or dplyr	+1.80
Assign intermediate output to temp variable as part of dplyr pipeline	-1.82
Superscript, subscript, and greek symbol all in one axis title in g...	0.00
How to average every 12 columns for each row in r	0.00
Getting all the children nodes of XML file to data.frame or data.ta...	0.00
Apply function only if columns respect condition	-2.47
R sqldf not recognizing posixct	0.00
In R, is it possible to create a new object inside a function and p...	-1.94
Find next date in series by group	-1.23
removing offset terms from a formula	+1.67
Convert fractional year and day of year to date in R	0.00
find max value in a data.frame by group and show its date as year-m...	+1.37
Mean matrix out of list of matrices	0.00
R dataframe: Getting value from next row subject to criteria	0.00
Extract sub-matrices from binary matrix in R	-1.04