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Weird parse in C++: int f(int(arg)) equivalent to int f(int arg) - can anyone explain it?
Author | Votes | Δ |
---|---|---|
Lightness Races in Orbit | 8 | +1.71 |
Jon Purdy | 3 | -1.71 |
Last visited: Nov 18, 2015, 10:10:27 PM